TEM wave solutions - wykład

TEM wave solutions We now note again that the equations 9.3 which we seek to solve are the same as those of
the lossless case studied in Chaper 8, except that ω² has been replaced by ω²−jσ. Thus a
corresponding set of solutions, with the same replacement, can be derived. We will quote
below the results which are obtained by making this replacement.
First the propagation vector, in the z direction, is
γ = α + jβ = j
q
ωμ(ω² − jσ) . (9.5)
Next the wave impedance is
η =
E1(0)
H1(0)
=
E0
H0
=
s
ωμ
ω² − jσ
. (9.6)
The spatial relation of the field components is preserved. The electric field E and the
magnetic field H are still at right angles, and E, H and β still form a right hand system
of vectors. Note, however, that E and H are no longer in time phase, because η is no
longer real.
We can distinguish now the important practical cases of small loss and large loss.
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